What happens when a Constructor gives a call to a virtual functions

What happens when a Constructor gives a call to a virtual functions

you shouldn't call virtual functions from a constructor because the vtable has not yet been setup at instantiation.
from MSDN: “When a virtual method is called, the actual type that executes the method is not selected until run time. When a constructor calls a virtual method, it is possible that the constructor for the instance that invokes the method has not executed“.
reference:
http://www.artima.com/cppsource/nevercall.html

class base
{
public:
 base()
 {
  cout<<"I am in base::base()"<<endl;
  foo();
 }
 virtual void foo(){cout<<"I am in base::foo()"<<endl;}
};

class derived:public base
{
public:
 derived()
 {
  cout<<"I am in derived::derived()"<<endl;
 }
 void foo(){cout<<"I am in derived::foo()"<<endl;}
};


int main(void) 
{ 
 derived d;
}

The output is: 
I am in base::base()
I am in base::foo()
I am in derived::derived()